∆ABC is an isosceles triangle such that AB=AC and AB:BC::13:11.if it's perimeter is 259 cm,then find the length of its sides[please solve step by step)
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Answer: 91cm, 91cm, and 77cm
Explanation:
Given, ∆ABC is an isosceles triangle such that AB=AC and AB:BC::13:11.
Let the side AB = AC = x
Let the side BC = 11/13 x
(Since AB:BC::13:11, BC = 11/13(AB) )
x + x + 11x/13 = 259
2x + 11x/13 = 259
(26x + 11x)/13 = 259
(26x + 11x) = 3367
37 x = 3367
x = 3367/37
x = 91
Therefore, the sides AB and AC = 91cm
Side BC = 11x/13
= 11(91)/13
= 11(7)
= 77cm
The sides of triangle ABC are 91cm, 91cm, and 77cm
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