Question

ABC is an isosceles triangle with ab=ac =10m and BC=12cm then the length of altitude from A to Bc is​

Answer 1

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Given

• AB = AC = 10cm
• BC = 12cm
• AN ⊥ BC

To Calculate

• Altitude of triangle

Solution

BC = BN + NC , BN = NC

BC/2 = 12/ 6 = BN = NC

In △ANB

AB = 10cm

BN = 6cm

By Pythagorous Theorem,

$\bf Hypotenuse {}^{2} = Base {}^{2} + Altitude {}^{2}$

$\bf \implies {10}^{2} = {6}^{2} + {Altitude}^{2}$

$\bf \implies 100 = 36 + {Altitude}^{2}$

$\bf \implies 100 - 36 = {Altitude}^{2}$

$\bf \implies {Altitude}^{2} = 64$

$\bf \implies {Altitude}^{2} = \sqrt{64}$

$\bf \implies {Altitude} = 8cm$

Therefore, Altitude of triangle is 8cm.