abc is an isosceles triangle with ab=ac =5 cm and bc =6 cm find sin c, tan b, tan c - cot b
Answers
Given : abc is an isosceles triangle with AB=AC =5 cm and BC =6 cm
To Find : sin c, tan b, tan c - cot b
Solution
AB=AC =5 cm
Draw AD ⊥ BC which is median too in isosceles triangle
=> BD = DC = BC/2 = 6/2 = 3cm
AB² - BD² = AD²
=> 5² - 3² = AD²
=> AD = 4 cm
sin c = AD/ AC = 4/5
tan b, = AD / BD = 4/3
=> Cotb = 3/4
tan c = AD/CD = 4/3
tan c - Cotb = 4/3 - 3/4 = (16 - 9)/12 = 7/12
Learn More:
the equal sides of an isosceles triangle is shown by a and the ...
https://brainly.in/question/11600587
ΔABC is an isosceles triangle in which AB=AC. Show that ∠B=∠C ...
https://brainly.in/question/4732240
Step-by-step explanation:
Your answers are attached above.
Please mark it as the brainliest and like my answers.
Don't worry the answers are 1000000000000000000% correct
Hope it helps :)
