abc is an isosceles triangle with ab=ac ad is perpendicular of angle bac prove angle b=angle c by congruence rule.
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In ΔABD and ΔACD
AB=AC
AD=AD
as perpendicular bisects the side BC
BD=CD
both triangles are congurent
so ∠B = ∠C
AB=AC
AD=AD
as perpendicular bisects the side BC
BD=CD
both triangles are congurent
so ∠B = ∠C
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