Question

ABC is an isosceles triangle with AB = AC and AD is one of its altitudes.

a) State the three pairs of equal parts in ∆ADB and ∆ ADC.

b) Is∆ ADB ≅ ∆ ADC? Why or why not?

c) Is BD = CD? Why Or why not?

d) Is ∠B = ∠C? Why or why not?​

Answer 1

Answer:

firstly make two triangle by breaking ΔABD and ΔACD

it would be congruent from RHS congruency rule

∠ADB=∠ADC=90°(as it is altitute) (R of RHS)

AB=AC(given) (H of RHS)

AD=AD ( common in both triangle)

now answers

(a)∠ADB=∠ADC=90°

AB=AC

AD=AD

(b) yes (as i have given above)

(c) yes as both the triangle are congruent they would be same

(d)yes as both the triangle are congruent they would be same

Step-by-step explanation:

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