ABC IS AN ISOSCELES triangle with AB=AC and angle A=50°.Calculate angle B
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Answered by
25
LET ANGLE B AND ANGLE C BE x ( SINCE, THE BASE ANGLES OF AN ISOSCELES TRIANGLE ARE EQUAL
BY ANGLE SUM PROPERTY,
ANGLE A +B+C = 180
50 +x+x = 180
50 + 2x = 180
2x = 180-50
x = 130/2
= 65
THEREFORE, ANGLE B = 65 DEGREE
BY ANGLE SUM PROPERTY,
ANGLE A +B+C = 180
50 +x+x = 180
50 + 2x = 180
2x = 180-50
x = 130/2
= 65
THEREFORE, ANGLE B = 65 DEGREE
Answered by
18
A +B+C = 180
50 +x+x = 180
50 + 2x = 180
2x = 180-50
x = 130/2
= 65
50 +x+x = 180
50 + 2x = 180
2x = 180-50
x = 130/2
= 65
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