Math, asked by AbhinavChavan, 5 months ago

ABC is an isosceles triangle with AB=BC and AD perpendicular BC. (3)

In ∆ ADB and ∆ACD

Answers

Answered by aroup01712

0

Answer:

what is this?....... ....

Answered by manasvistangirala

0

Answer:

Angle ADB = Angle ADC (as AD is perpendicular to BC)

Angle ABD = Angle ACD ( ABC is isocelese)

AD=AD (common)

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