ABC is an isosceles triangle with ab is equal to AC draw AP prepandicular BC to show that angle b is equal to C
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Answered by
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GIVEN,
ABC is an isosceles triangle with
AP=AC
AP perpendicular BC
proof
In triangle ABC
AB=AC
angle ACB=ABC...........(1)
AB=AC
angleABP=ACP
angle APB=ACP.........(90°)
TRIANGLE APB CONGURANCE APC
angleABP=angleACP
angleB=angleC
hope you like it... please mark brain list
ABC is an isosceles triangle with
AP=AC
AP perpendicular BC
proof
In triangle ABC
AB=AC
angle ACB=ABC...........(1)
AB=AC
angleABP=ACP
angle APB=ACP.........(90°)
TRIANGLE APB CONGURANCE APC
angleABP=angleACP
angleB=angleC
hope you like it... please mark brain list
Answered by
1
Hello mate ^_^
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Solution:
In △ABP and △ACP
AB=AC (Given)
∠APB=∠APC (Each equal to 90°)
AP=AP (Common)
Therefore, by RHS congruence rule, △ABP≅△ACP
Hence, ∠B=∠C (Corresponding parts of congruent triangles are equal)
hope, this will help you.
Thank you______❤
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