Question

ABC is an isosceles triangle with ab is equal to AC is equal to 7.5 cm and BC is equal to 9 cm height from a to b c is 6 cm find the area of triangle ABC what will be the height from c to Ab and ce

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

$Height \:from \:C\: to\: AB \\= EC = 7.2 \: cm$

$Height \: from \: B \: to \: AC\\ = EC = 7.2 \: cm$

Step-by-step explanation:

Given ,

ABC is an isosceles triangle.

AB = AC = 7.5 cm

BC = 9 cm,

AD = 6 cm

$\boxed { Area\: of \:a\: triangle = \frac{base\times altitude }{2}}$

$i) Area\: of \:triangle\: ABC = \frac{BC\times AD}{2}\\=\frac{9 \times 6}{2}\\=27 \: cm^{2}--(1)$

$ii) \frac{AB\times CE}{2}=Area \: of \: triangle\: ABC$

$\implies \frac{7.5 \times EC }{2}= 27 cm^{2}$

/* From (1) */

$\implies EC =\frac{ 27 cm^{2}\times 2}{7.5\cm}$

$Height \:from \:C\: to\: AB \\= EC = 7.2 \: cm$

$Height \: from \: B \: to \: AC = EC = 7.2 \: cm$

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