If a×a + b×b + c×c =220 & ab + bc + ca = 4 . then, find the value of a + b + c
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a^2 + b^2 + c^2 =220
ab+bc+ca=4
(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca)
⇒ (a+b+c)^2 = 220 + 2(4)
⇒ (a+b+c)^2 = 220+8
⇒ (a+b+c)^2 = 228
⇒ a+b+c = √228
ab+bc+ca=4
(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca)
⇒ (a+b+c)^2 = 220 + 2(4)
⇒ (a+b+c)^2 = 220+8
⇒ (a+b+c)^2 = 228
⇒ a+b+c = √228
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