ABC is an isosceles triangle with ac is equal to BC if a b square is equal to 2 AC square who prove that ABC is an right angle triangle
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Answer:AC=BC (given)
AC²=BC²
Given: AB²=2AC²
AB²=AC²+AC²
AB²=AC²+BC²
So, AB is hypotenuse then angleC is of 90° and thus triangle ABC is a right angle triangle
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In triangle ABC
AC=BC
Given:
AB^2=2AC^2
AB^2=AC^2+BC^2(since AC=BC)
This satisfies the Pythagoras Theorem
Therefore ABC is a right angled triangle.
Hope it helps...
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