Question

abc is an isosceles triangle with side ab=ac=3x-4=3x/4+32 the area of equilateral triangle with sides of length x is (who tell i will give him 80 points)

Answer 1

Step-by-step explanation:

$given \: that \\ 3x - 4 = \frac{3x}{4} + 32 \\ \\ 3x - \frac{3x}{4} = 32 + 4 \\ \\ \frac{12x - 3x}{4} = 36 \\ \\ \frac{8x}{4} = 36 \\ \\ x = \frac{36}{2} \\ \\ x = 18$

If the side of equilateral triangle is x, the area is,

$\frac{ \sqrt{3} }{4}{x}^{2} \\ \\ = \frac{ \sqrt{3} \times 18 \times 18 }{4} \\ \\ = \sqrt{3} \times 9 \times 9 \\ \\ = 81 \sqrt{3}$

Hope it helps!