Question

Find the equation of the circle with center at (3, -2) and radius of 3.

Answer 1

Answer:

( x - 3 )² + ( y + 2 )² = 9

Step-by-step explanation:

Given :

Center points of circle ( 3 , - 2 ) & radius 3 units!

We are asked to find equation of circle :

We know standard equation of circle :

( x - h )² + ( y - k )² = r²

Where ( h , k ) represents Center points of circle and r represent radius!

Putting values here we get :

( x - 3 )² + ( y - ( - 2 ) )² = 3²

= > ( x - 3 )² + ( y + 2 )² = 9

Hence we get required equation of circle!

Answer 2

GiveN :

Centre points are (3,-2)

Radius = 3 unit

To FinD :

Equation of circle

SolutioN :

Use formula for the circle :

$\dashrightarrow \boxed{\tt{(x \: - \: h)^2 \: + \: (y \: - \: k)^2 \: = \: r^2}} \\ \\ \dashrightarrow \tt{(x \: - \: 3)^2 \: + \: (y \: - \: (-2))^2 \: = \: 3^2} \\ \\ \dashrightarrow \tt{(x \: - \: 3)^2 \: + \: (y \: + \: 2)^2 \: = \: 9}$

_____________________

Additional Information :

• If centre is (0, 0), then equation of circle is x² + y² = a²

• When the circle passes through the origin, then equation of the circle is x² + y² - 2hx - 2ky = 0

• When the circle touches the x-axis, the equation is x² + y² - 2hx - 2ay + h² = 0

• Equation of the circle, touching the Y-axis is x² + y² - 2ax - 2ky + k² = 0.