ABC is an isoscles triangle with AB=AC and angle = 50 degree calculate angle B
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angle b is 65° is right
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LET ANGLE B AND ANGLE C BE x ( SINCE, THE BASE ANGLES OF AN ISOSCELES TRIANGLE ARE EQUAL
NOW BY
ANGLE SUM PROPERTY,
ANGLE A +B+C = 180
50 +x+x = 180
50 + 2x = 180
2x = 180-50
x = 130/2
= 65
THEREFORE, ANGLE B = 65 DEGREE
NOW BY
ANGLE SUM PROPERTY,
ANGLE A +B+C = 180
50 +x+x = 180
50 + 2x = 180
2x = 180-50
x = 130/2
= 65
THEREFORE, ANGLE B = 65 DEGREE
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