Question

△ABC is given with a right angle, ∠B, cos(3x+30)°=sin(12x)°. If ∡A=(3x+30)°, what is the value of ∡A? Explain.

A. ∡A=60° since 3x+30=12x and x=10.

B. ∡A=40° since 3x+30=12x and x=103.

C. ∡A=42° since 3x+30+12x=90 and x=4.

D. ∡A=48° since 3x+30+12x=90 and x=4.

Answer 1

Answer:

△ABC is given with a right angle, ∠B, cos(3x+30)°=sin(12x)°. If ∡A=(3x+30)°, what is the value of ∡A? Explain.

A. ∡A=60° since 3x+30=12x and x=10.

B. ∡A=40° since 3x+30=12x and x=103.

C. ∡A=42° since 3x+30+12x=90 and x=4.

D. ∡A=48° since 3x+30+12x=90 and x=4.

thus a is the answer

Answer 2

"If you recall:

cos k = sin (90 - k) and sin p = cos (90-p)

given: cos(3x + 10) = sin(12x)

cos(3x+10) = sin (90 - 3x - 10)

but we are given that: cos(3x+10) = sin(12x)

so 12x = 80-3x

15x = 80

x = 80/15 = 16/3

so angle A = 3x+10

= 3(16/3) + 10 = 26°

which would make angle B = 64°

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