Question

∆ABC is inscribed in a circle with centre O . Seg AE is the diameter . Tangent to the circle at point E intersects line AB in the point X and line AC in the point Y .
Prove that : AB×AX=AC×AY​

Answer 1

$\huge\red{\boxed{HELLO\:MATE}}$

$\huge\red{\boxed{HELLO\:MATE}}$

$\huge\red{\boxed{HELLO\:MATE}}$

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Answer 2

Answer:

it can be done by tangent secant segment theorem