Question

abc is isosceles in which ae is perpendicular to bc ,ae=6cm,bc=9cm, the area of∆abc is

Answer 1

Answer:

27cm^2

Step-by-step explanation:

Area of a triangle=(1/2)×base×height where ae=height=6cm and bc=base=9cm

Thus applying the formula, we get

=(54cm^2)/2

= 27cm^2

Answer 2

The area of ΔABC is 27 cm².

Given :

∆ABC is isosceles

AE is perpendicular to BC,

AE = 6cm and BC = 9cm.

To find:

Area of ΔABC

Solution:

• An isosceles triangle is a type of triangle in which two sides have the same length. These two sides are known as the legs of the triangle and the third side, which connects the two legs, is called the base.

We know that in an isosceles triangle, the perpendicular bisector of the base is also the median and the altitude.

So, the area of the triangle will be (1/2)CAE = (1/2)96 = 27cm²

Therefore the area of ∆ABC is 27cm².

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