ABC is isosceles triangle with ab =aC and Angle A is 90 then find the value of cos B
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in ∆ABC, AB=AC.
angleA=90°
therefore, angleB=angleC=45°
therefore, cosB=cos45°
=1/√2.
hope it helps.
angleA=90°
therefore, angleB=angleC=45°
therefore, cosB=cos45°
=1/√2.
hope it helps.
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