∆ ABC is isosceles with AB=BC. If angle B is thrice the measure of angle A, Find the measures of all the angles of the Triangle.
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Here you go .........
Step-by-step explanation:
If AB = CB then angle A = angle C
Given that ∠B = 3∠A
We know that in a triangle sum of all angles is 180°
∠A+∠B+∠C = 180°
∠A+3∠A+∠A = 180
5∠A = 180
∠A = 36°
∠C = ∠A = 36°
∠B = ∠3A = 3(36°) = 108°
Therefore the angles of the triangle are 36°, 36°, 108°
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