Question

ABC is right angle triangle in which angle A equal to 63 degree angle B equals to 27 degree. ACFG and BCDE are squares drawn external to the triangle ABC such that AE intersects BC at H .BG intersects AC at K. angle DKH equal to what

Answer 1

Answer:

45°

Step-by-step explanation:

   AC = a

   BC = b

tan 27 = a / b

tan FBG = a / a + b

            = KC / b

         KC = ab / a + b

tan DAH = b / a + b

              = CH / a

         CH = ab / a + b

Now,  KC = CH

2 ∠DKH = 90°

 ∠DKH = 45°