abc is right angled at c and cd perpendicular ab also angle a is 65 degree find angle acd bcd cbd
Answers
Answered by
53
In ∆ADC ,
angle A + angle B + angle C = 180°
..............sum of measure of angle
of triangle
therefore , 90+65+angleACD=180°
angle ACD = 180°-155°
angle ACD = 25°
In ∆ABC ,
Angle A + angle B + angle C = 180°
therefore, AngleCBD = 25°
In ∆CBD , by applying SMAT
we can find Angle BCD=65°
angle A + angle B + angle C = 180°
..............sum of measure of angle
of triangle
therefore , 90+65+angleACD=180°
angle ACD = 180°-155°
angle ACD = 25°
In ∆ABC ,
Angle A + angle B + angle C = 180°
therefore, AngleCBD = 25°
In ∆CBD , by applying SMAT
we can find Angle BCD=65°
Similar questions