Question

ΔABC is right-angled at C. If AC=10cm, BC=24cm, find AB.

Answer 1

Answer:

26 cm

Step-by-step explanation:

by pythagoras theorem

AB^2=AC^2+BC^2

=100+576

=676

676 is perfect square of 26

so 26 cm is correct answer

Answer 2

Answer

26cm

Step-by-step explanation

$AC^{2}$$+BC^{2} =AB^{2}$

$10^{2} +24^{2} =AB^{2}$

100+576$=AB^{2}$

676=$AB^{2}$

26=AB

HOPE IT HELPS GUYS