Abc is right angled. The measures of the sides forming right angle are x and y. The radius of the circle touches all the sides of triangle abc is:
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As ABC IS A RIGHT ANGLE TRIANGLE
AREA WILL BE EQUAL TO 1/2 ×B×H
ALSO JOIN A TO CENTER O AND B TO CENTRE O AND C TO CENTER O. ALSO DRAW TANGENTS FROM O TO SIDE AB, BC, AC.
NOW THE SUM OF AREA OF TRIANGLE AOB, BOC, AOC WILL EQUAL TO AREA OF WHOLE TRIANGLE..
IMPORTANT :(USE FORMULA 1/2×B×H, WHERE H=R)
AC WILL BE EQUAL TO x+y-2r(tangent from o to AC And BC forms a quad. Which is square as all the angles are equal and adjacent sides are equal. Tangent from common pt. To circle are equal so AC Will equal to x+y-2r)
U will get the answer
AREA WILL BE EQUAL TO 1/2 ×B×H
ALSO JOIN A TO CENTER O AND B TO CENTRE O AND C TO CENTER O. ALSO DRAW TANGENTS FROM O TO SIDE AB, BC, AC.
NOW THE SUM OF AREA OF TRIANGLE AOB, BOC, AOC WILL EQUAL TO AREA OF WHOLE TRIANGLE..
IMPORTANT :(USE FORMULA 1/2×B×H, WHERE H=R)
AC WILL BE EQUAL TO x+y-2r(tangent from o to AC And BC forms a quad. Which is square as all the angles are equal and adjacent sides are equal. Tangent from common pt. To circle are equal so AC Will equal to x+y-2r)
U will get the answer
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