ABC is right angled triangle right angled at B with AB=12cmBC=5cm a circle is inscribed in this triangle find the radius of circle
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Since ABC is a right angled triangle,
∴AB²+BC²=AC²
12²+5²=AC²
144+25=AC²
⇒AC²=169
AC=√169=13 cm
Perimeter of the triangle=12+5+13=30
Circumference of the circle=30
∴2πr=30
2×22/7×r=30
r= 30×7/2×22
r=4.8.. cm
HOPE THIS HELPS YOU!!
∴AB²+BC²=AC²
12²+5²=AC²
144+25=AC²
⇒AC²=169
AC=√169=13 cm
Perimeter of the triangle=12+5+13=30
Circumference of the circle=30
∴2πr=30
2×22/7×r=30
r= 30×7/2×22
r=4.8.. cm
HOPE THIS HELPS YOU!!
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