Abc is right triangle at b bd perpendicular to hypotenuse a.c. bd=8 ,da= 4 . Find length cd
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Given ∠ABC=90∘,BD is perpendicular to AC, BD=8,andAD=4, as shown in the diagram.
Let ∠ACB=x,⇒∠CBD=90−x
⇒∠ABD=x,⇒∠BAD=90−x
⇒ΔABC,ΔADB,andΔBDC are similar
⇒BDCD=ADDB
⇒8CD=48
⇒CD=8×84=16
Let ∠ACB=x,⇒∠CBD=90−x
⇒∠ABD=x,⇒∠BAD=90−x
⇒ΔABC,ΔADB,andΔBDC are similar
⇒BDCD=ADDB
⇒8CD=48
⇒CD=8×84=16
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