Question

if 3cosA =4sinA find 4cos square A -3sin square A +2

Answer 1

since

3cosA=4sinA,


then
tanA=3/4,

then

sinA=3/5,

cosA=4/5,


therefore


4cos²A-3sin²A+2,


4×(4/5)²-3×(3/5)²+2,


4×16/25 - 3×9/25 +2,


64/25 - 27/25 + 2,


(64-27+50)/25,


87/25

Answer 2

Answer:

87/25 is the answer of this question