Question

ABC is the cross-section of the prism.Find the surface area of the prism if AB=AC=5cm,BC=6cm and CR=8cm

Answer 1

Answer:

152 cm²

Step-by-step explanation:

Surface area of an isosceles triangular prism

= bh + 2ls + lb

where,

b = base of prism = BC = 6 cm (given)

h = height of prism

l = length of prism = CR =8 cm

s = equal sides of isosceles triangle = AB = AC = 5 cm

using Pythagoras theorem

(height of prism)² = (AC)² - (1/2BC)²

(height of prism)² = (5)² - (3)² = 25 - 9 = 16

height of prism = √16 = 4cm

Surface area = bh + 2ls + lb

Surface area = (6)(4) + 2(8)(5) + (8)(6) = 24 + 80 + 48

Surface area = 104 + 48 = 152 cm²

Answer 2

Answer:

Step-by-step explanation: