ABC is triangle right angled at B and its in circle has 3cm radius and the other incircle has radius 1cm touches sides AC,BC find AB
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from the given information
Step-by-step explanation:
this is in circle
BO = 3√2 and OD = 3cm
BD = BO + OD = 3 + 3√2 cm
BD is angular bisector of Angle ABC
then angle ABD =45°
triangle ABD will be isosceles right angle triangle
in ratio 1:1:√2
then
√2 × (base or height)
AB is the hypotenuse of triangle ABD
AB = √2 × AD = √2 × BD
AB = √2 × (3+3√2)
AB = 6 + 3√2 cm
hope you get it....
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