Question

ABC is triangle right angled at B and its in circle has 3cm radius and the other incircle has radius 1cm touches sides AC,BC find AB

Answer 1

Answer:

from the given information

Step-by-step explanation:

this is in circle

BO = 3√2 and OD = 3cm

BD = BO + OD = 3 + 3√2 cm

BD is angular bisector of Angle ABC

then angle ABD =45°

triangle ABD will be isosceles right angle triangle

in ratio 1:1:√2

then

√2 × (base or height)

AB is the hypotenuse of triangle ABD

AB = √2 × AD = √2 × BD

AB = √2 × (3+3√2)

AB = 6 + 3√2 cm

hope you get it....

Answer 2

Answer:

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