Question

∆ABC of AB=AC. Angle B=half of angle A.find the measure of all angle​

Answer 1

Answer:

∠B = ∠C ( AB = AC )

∠B = ∠C = 1/2 ∠A

Sum of all the three angles of Δ = 180

∠A + ∠B+ ∠C =180

∠A + 1/2 ∠A +1/2∠A = 180

∠A + ∠A = 180

2∠A =180

∠A= 180 /2 = 90

∠B = 1/2∠A = 90 / 2= 45

∠C = ∠B = 45

Answer 2

A=36andC=36 and B=18 this is the measure of the all angles of triangle ABC