∆ abc ~ ∆pqr, a(∆abc) =81cm2, if ab=6, pq=12cm, find a(∆pqr)
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Step-by-step explanation:
A(∆ABC). AB^2
--------------= ----------. ----(theorem of areas of
A(∆PQR). PQ^2. similar triangle)
81. 6^2
--------. =. -------
A(∆PQR). 12^2
A(∆PQR) = 81×144
-----------
36
A(∆PQR)= 324 cm^2
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