Question

∆ABC ~ ∆PQR, AC = 8cm, PR = 4 cm, QR = 6 cm then find BC.

Answer 1

Answer:

if triangle ABC equal to triangle pqr is equal to 8 cm and PR equal to 4 cm and QR is equal to 6 CM

Step-by-step explanation:

faster we have to draw a of AC and then draw the sides line of a triangle like PR and QR and in the same way draw the triangle store triangle pqr is equal to abc

Answer 2

Answer:

Ratio of area∆ABC and area ∆PQR = \frac{16}{9}

9

16

Step-by-step explanation:

By Theorem:

The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.

Here,

∆ABC ~ ∆PQR

BC = 8 cm,

QR = 6 cm

Ratio of area∆ABC and area ∆PQR

= Ratio of the squares of their corresponding sides

= \frac{BC^{2}}{QR^{2}}

QR

2

BC

2

= \frac{8^{2}}{6^{2}}

6

2

8

2

= \frac{64}{36}

36

64

= \frac{16}{9}

9

16

Therefore,

Ratio of area∆ABC and area ∆PQR = \frac{16}{9}

9

16