∆(ABC) ~∆(PQR),are of triangle ABC = 36 cm square and area of PQR=25 cm square if QR =6cm ,find BC
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Or,ABC/PQR=BC/QR
Or,36/25=BC/6
Or,36*6=25BC
Or,216=25BC
Or, BC=216/25
Or, BC=8.64
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