∆ ABC ~ ∆ PQR, <A=53°and <Q= 77° find <B?
ANSWER Me Please
Answers
Answered by
1
Answer:
Angle B is = 50 degree
Step-by-step explanation:
we will use angle sum property,
aA + aB + aC = 180
53+ aB + 77 = 180
aB + 130 = 180
angle B = 180-130
= 50 degree
Answered by
3
Answer:
Here is the answer to your question
Given,
∠A = 53° , ∠Q = 77°
∴ ∠A + ∠Q + ∠R = 180°
= 53°+77°+∠R = 180°
= ∠R = 180° - 53° - 77°
= ∠R = 50°
Hence, the correct answer is 50°
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