ΔABC ≅ ΔPRQ and AB = 5 cm, BC = 6 cm, AC = 7 cm, what is the length of QR?
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Step-by-step explanation:
Given, △ABC∼△PQR, as corresponding sides of similar triangles are proportional,
∴
PQ =AB = QR =BC = RP -CA = k 1 (let)
Also, AB=5,BC=6,AC=7 So, PQ=5k,QR=6k,RP=7k
Perimeter of △PQR=PQ+QR+RP
⇒360=5k+6k+7k⇒360=18k⇒k=20
Thus, PQ=5×20=100,QR=6×20=120,RP=7×20=140
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