abc+xy, 3xy-13abc,Subtract the given terms.
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Solution :
Given first expression = abc + xy
second expression = 3xy - 13abc
Now ,
i ) Subtract second expression from
first , we get
abc + xy - ( 3xy - 13abc )
= abc + xy - 3xy + 13abc
= abc + 13abc + xy - 3xy
= ( 1 + 13 )abc + ( 1 - 3 )xy
= 14abc - 2xy
ii ) Subtracting first expression from
second , we get
=> 3xy - 13abc - ( abc + xy ).
= 3xy - 13abc - abc - xy
= 3xy - xy - 13abc - abc
= ( 3 - 1 )xy + ( -13 - 1 )abc
= 2xy - 14abc
••••
Given first expression = abc + xy
second expression = 3xy - 13abc
Now ,
i ) Subtract second expression from
first , we get
abc + xy - ( 3xy - 13abc )
= abc + xy - 3xy + 13abc
= abc + 13abc + xy - 3xy
= ( 1 + 13 )abc + ( 1 - 3 )xy
= 14abc - 2xy
ii ) Subtracting first expression from
second , we get
=> 3xy - 13abc - ( abc + xy ).
= 3xy - 13abc - abc - xy
= 3xy - xy - 13abc - abc
= ( 3 - 1 )xy + ( -13 - 1 )abc
= 2xy - 14abc
••••
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