ABCD and EFGH are parallelograms where ADparallel BC and EH parallel FG .find x if angle EFG is equal to 65 and angle ADG is equal to 130
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Given:AD parallel to BC.
EH parallel to FG.
/_EFG=65°.
/_ADG=130°.
Solution: Three sides of triangles =180°
/_EFG+/_ADG= x
65°+ 130°=195°-180°....
(all sides of triangles are 180°)
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• • x = 15°
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