Question

ABCD and PQRC are rectangles and Q is the mid point of AC. Prove that DP=PC and PR=1/2AC.

Answer 1

i)) In ΔADC,Qis the midpoint of AC such that PQ║AD

∴P is the midpoint of DC

⇒ DP = DC

ii) similarly, R is the midpoint of BC

∴PR= 1/2 BD

[diagonal of rectangle are equal∴BD=AC]

PR =1/2 AC

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