Question

abcd and pqrs are 2 squares such that area of square pqrs is A m^2 then find the value of √17A
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Answer 1

Answer:

your answer is here

first, area of square PQRS whose side is 16cm:-

s×s = 16×16=256

Now area of square ABCD:-

area of square PQRS + area of square ABCD

=3969+256= 4225

therefore, s×s=4225

which implies that s=root of 4225

therefore s= 65

now perimeter of square ABCD = 4 × s :-

4×65= 260cm

which is the required perimeter.

hope it will help you