Question

ABCD and PQRS are rectangles and Q is the mid point of AC. prove that,
(1)DP=PC
(2)PR=1/3AC

Answer 1

u should refer the mid point theorem

Answer 2

Answer:

Step-by-step explanation:

In ΔADC,Q is the mid-point of AC such that PQ∥AD.

∴P is the mid-point of DC

⇒DP=PC [Using converse of mid-point theorem]

Similarly, R is the mid-point of BC.

∴PR=  

2

1

​

BD

⇒PR=  

2

1

​

AC     [∵BD=AC]