Question

ABCD ia parallelogram.
E is the point of ray AD.
EB interects DC is point F.
prove that
∆AEB ~ ∆CFB
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Answer 1

Answer:

Step-by-step explanation:

➡️In a parallelogram opposite angles are equal to each other. Then find the relation between angles of both triangle's to show them similar.

➡️If two angles of a triangle are respectively equal to two angles of another triangle, then Triangles are similar (because by the angle sum property of a triangle their third angle will also be equal ) and it is called AA similarity criterion.

➡️In ΔABE and ΔCFB,

∠A = ∠C (Opposite angles of a parallelogram)

∠AEB = ∠CBF (Alternate interior angles as AE || BC)

∴ ΔABE ~ ΔCFB (By AA similarity criterion)

Hope this will help you..

Answer 2

Answer:

In a parallelogram opposite angles are equal to each other. then find the relational between angle of both triangles's to show them similar.

Hope it help you❤❤