abcd in which AB=5,BC=4,CD=6,AD=6and angleB=80°
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Let AB=11 cm, CD=6 cm and AB is parellel to CD.
Let distance between foot of perpendicular h and A
is X.
So distance between B and foot of 2nd perpendicular from C=11–6-x=5-x.
There are 2 rt. angled triangles.
Applying Pythogorous theorem,
For one triangle,
h^2=3^2-x^2—————(1)
For 2nd triangle,
h^2=4^2-(5-x)^2————-(2)
From (1)&(2), x=1.8 cm and
required h=2.4 cm
Let distance between foot of perpendicular h and A
is X.
So distance between B and foot of 2nd perpendicular from C=11–6-x=5-x.
There are 2 rt. angled triangles.
Applying Pythogorous theorem,
For one triangle,
h^2=3^2-x^2—————(1)
For 2nd triangle,
h^2=4^2-(5-x)^2————-(2)
From (1)&(2), x=1.8 cm and
required h=2.4 cm
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