Math, asked by laxmigupta9792, 2 months ago

ABCD in which AB = 8 cm, BC = 6 cm, CD = 4 cm, AD = 5 cm and ΔB = 60°.​

Plz answer this Q. step-by-step​

Answers

Answered by antrakurrey
0

Answer:

Construct a quadrilateral

ABCD given that BC = 6 cm, CD = 4 cm, B = 45^· , C = 90^· and D = 120^·

Answered by nilimaipu3456
1

Answer:

GIVEN : In Trapezium ABCD,

AB || CD

AB = 8 cm

BC = 6cm

CD = 4cm

∠B = 60o.

PROCEDURE :

Step1 : draw a rough sketch and mark the measurements given.

As it is given that AB || CD , so ∠B + ∠C = 180° (linear pair). So ∠C = 180° – 60° = 120°



Step 2 : draw ΔABC using SAS construction rule with measures AB = 8 cm, ∠B = 60o and BC = 6 cm.



Step 3 : construct ∠C = 120° and draw CY.



Step 4 : with center ‘C’ and radius 4cm (CD = 4 cm) draw an arc to intersect CY at D. Join A,D . ABCD is the required quadrilateral (trapezium).



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