ABCD in which AB = 8 cm, BC = 6 cm, CD = 4 cm, AD = 5 cm and ΔB = 60°.
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Construct a quadrilateral
ABCD given that BC = 6 cm, CD = 4 cm, B = 45^· , C = 90^· and D = 120^·
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Answer:
GIVEN : In Trapezium ABCD,
AB || CD
AB = 8 cm
BC = 6cm
CD = 4cm
∠B = 60o.
PROCEDURE :
Step1 : draw a rough sketch and mark the measurements given.
As it is given that AB || CD , so ∠B + ∠C = 180° (linear pair). So ∠C = 180° – 60° = 120°

Step 2 : draw ΔABC using SAS construction rule with measures AB = 8 cm, ∠B = 60o and BC = 6 cm.

Step 3 : construct ∠C = 120° and draw CY.

Step 4 : with center ‘C’ and radius 4cm (CD = 4 cm) draw an arc to intersect CY at D. Join A,D . ABCD is the required quadrilateral (trapezium).

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