Abcd is a cyclic quadrilateral and ab is the diameter of the circle. if ∠cab = 48°, then what is the value (in degrees) of ∠adc?
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In a cyclic quadrilateral,opposite angles are congurent.
So,if <cab=48°
<bdc=180-48=132°
to find <adc, join ad... Line ad bisect <d
------> <adc=<d/2
=132/2=62°
So,if <cab=48°
<bdc=180-48=132°
to find <adc, join ad... Line ad bisect <d
------> <adc=<d/2
=132/2=62°
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