divide 7+3x3 with 7+3x and write the denominator and quotient
Answers
Answered by
1
7+3x^3 ÷ 7 + 3x
Arranging them we get,
x^2 - 2.3x - 5.367
________________
3x + 7) 3x^3 + 0x^2 + 0x + 7
(-)3x^3 + 7x^2
-7x^2 + 0x
(-) -7x^2 + 16.1x
- 16.1x + 7
(-) - 16.1x + 37.569
_______
-30.569
______
Quotient = x^2 - 2.3x - 5.367
Remainder = -30.569
Arranging them we get,
x^2 - 2.3x - 5.367
________________
3x + 7) 3x^3 + 0x^2 + 0x + 7
(-)3x^3 + 7x^2
-7x^2 + 0x
(-) -7x^2 + 16.1x
- 16.1x + 7
(-) - 16.1x + 37.569
_______
-30.569
______
Quotient = x^2 - 2.3x - 5.367
Remainder = -30.569
Answered by
16
Answer:
Quotient = x² - 2.3x - 5.367
Remainder = 30.569
Hope it will be helpful ✌️
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