Question

ABCD is a cyclic quadrilateral . Angle A 3x-5,angle B 4x,+10,angle c -7y +5 and angle D -4y . Find the angle of quadrilateral

Answer 1

GIVEN
ABCD is a cyclic quadrilateral
Angle A = 3x - 5
Angle B = 4x + 10
Angle C = 7y + 5
Angle D = 4y + 10
USE
Angle A + angle B = 180 degrees.... (1)
Angle C + angle D = 180 degrees..... (2)
and
Angle A + angle B + Angle C + angle D
= 360 degrees
Therefore, by (1)
3x- 5 + 4x,+10 = 180
7x + 5= 180
7x = 180 - 5
7x = 175
x = 175 / 7
x = 25 degrees
Angle A = (3 x 25) - 5 = 75 - 5 = 70 degrees
ANGLE B = (4 x 25) + 10 = 100+10 = 110 degrees
By given statement
7y +5 = 110
7y = 110 - 5
Y = 105 / 7
y = 15 degrees
Angle C = (7x15) + 5 = 110
Angle D = (4 x 15 + 10) = 70

Therefore, angles of cyclic quadrilateral are
Angle A = 70, angle B = 110, angle C = 110 & angle D = 70

Answer 2

Answer:

PLEASE MARK ME A BRAINLIEST ANSWER