ABCD is a cyclic quadrilateral if AD || BC and angle B = 70° find the other angles of ABCD
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angle D = angle B = 70°
angle A + angle B = 180° [by linear pair]
angle A = 180 - 70
= 110°
angle C = angle A = 110°
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Answered by
20
Given AD//BC
so ANGLE B + ANGLE C = |80. ( by linear pair)
70 + ANGLE C = |80.
ANGLEC = |80 - 70
ANGLE C = ||0
Similarly ANGLE D= 70
and ANGLE A = ||0
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so ANGLE B + ANGLE C = |80. ( by linear pair)
70 + ANGLE C = |80.
ANGLEC = |80 - 70
ANGLE C = ||0
Similarly ANGLE D= 70
and ANGLE A = ||0
HOPE U UNDERSTAND AND IF U HAVE ANY DOUBT THEN COMMENT ,PLZ MARK ME BRAINLIST IF U LIKE THE ANSWER
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