ABCD is a cyclic quadrilateral in
which AB = AD. angle BCD = 70°.
Find (i) m (arc BCD) (ii) m (arc BAD)
(iii) angle ADB.
Answers
Answered by
29
m (arc BCD) =220° , m (arc BAD) = 140° , ∠ADB= 35°
Step-by-step explanation:
ABCD is a cyclic quadrilateral in
which AB = AD
∠BCD = 70°
angle by BD at center = 2 * 70° = 140°
=> m (arc BCD) = 360° - 140° = 220°
m (arc BAD) = 360° - 220° = 140°
∠BCD = 70°
∠BAD + ∠BCD = 180° ( cyclic quadrilateral)
=> ∠BAD + 70° = 180°
=> ∠BAD = 110°
in Δ ADB
AB = AD
=> ∠ADB = ∠ABD
∠BAD + ∠ADB + ∠ABD= 180°
=> 110° + ∠ADB + ∠ADB= 180°
=> 2∠ADB= 70°
=> ∠ADB= 35°
Learn more:
ABCD एक चतुर्भुज है जिसमें AB=AD और BD=CD और DBC=2 ...
https://brainly.in/question/15266081
In the given figure, angle AOC=46°. Find angle ABC - Brainly.in
https://brainly.in/question/15058850
In a circle with centre o an arc abc subtends an angle of 110 degree at
https://brainly.in/question/15421783
Answered by
19
Hope this helps you
Thank you
Mark it as brainliest...
Attachments:
Similar questions