Abcd is a cyclic quadrilateral such that angle a =4y+20°,b =3y-5°,c=4x°,d=7x+5° .Find the four angles
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Answered by
1
Concept:
Opposite angles of a cyclic quadrilateral
are supplementary.
Given:
∠A = 4y+20
∠B = 3y-5
∠C = - 4x
∠D = 7x+5
since Opposite angles of a cyclic quadrilateral are supplementary,
we have
∠A+∠C = 180°
4y+20-4x = 180
-4x+4y = 160
-x+y = 40.........(1)
and
∠B+∠D = 180°
3y-5+7x+5 = 180
7x+3y= 180.....(2)
-7x+7y= 280 (multiplying (1) by 7)
10y = 460
y= 46
(1)gives
-x+46=40
-x= -6
x=6
Answered by
2
Answer:
in a cyclic quadrilateral sum of oposite angle =180
ang. a is opposite to ang. c
similarly ang. b to ang. d
4y +20 + 4x = 180
3y - 5 +7x+ 5 = 180
now just solve these two with elimination or subditution and you will get your x and y
hope it helps
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