Question

Abcd is a cyclic quadrilateral whose diagonals intersect with at a point



e.If dbc = 70° bac is 30° find bcd,further if ab= bc find ecd

Answer 1

Hello mate =_=

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Solution:

∠BAC=∠BDC      (Angles in the same segment)

⇒∠BDC=30°

We also have ∠BDC+∠DBC+∠BCD=180°

⇒30°+70°+∠BCD=180°

⇒∠BCD=180°−70°−30°=80°

If, AB=BC then we have ∠BCA=∠BAC

(Angles opposite to the equal sides of a triangle are equal.)

⇒∠BCA=30°

We have just found above that ∠BCD=80°

∠ECD=∠BCD−∠BCA

⇒∠ECD=80°−30°=50°

I hope, this will help you.

Thank you______❤

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