ABCD is a cyclic quadrilateral with angle ADC=135° sides BA and CD produced and meets at point P, sides AD and BC produced and meets at Q. if angle P: angle Q=2:1 find angles P and Q
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x=45°...................
2x=2×45=90°
1x=1×45=45°
so Angle P=90°
Angle Q=45°
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